Results from a local survey asked where coffee drinkers typically drink their first cup of coffee. To determine whether this distribution has changed, you randomly select 581 coffee drinkers and ask each where they typically drink their first cup of coffee. The results are listed in the table.
Your Local Survey Results - O's
At Home |
389 |
At Work |
110 |
During Commute |
55 |
Coffee Shop |
27 |
A national study had the results are below.
The National Survey Results - E's
At Home-34% |
406.70 |
At Work-17% |
98.77 |
During Commute-8% |
46.48 |
Coffee Shop-5% |
29.05 |
Does the Local Survey seem to match the National Survey? Use
alphaα
= 0.05.
Hypotheses
Upper H 0H0:
The Local Survey data is a good fit to the National Survey.
Upper H 1H1:
The Local Survey data is not a good fit to the National Survey.
Calculate the Test Statistic and P-value.
Test Statistic
chi squaredχ2
= nothing
P-value p = nothing
Test result
P-value
nothing
alphaα
A.Do not reject
Upper H 0H0.
B.Reject
Upper H 0H0.
Choose the correct conclusion below.
A.
The data is a good fit.
B.
The data is not a good fit.
Click to select your answer(s).
applying chi square goodness of fit test: |
relative | observed | Expected | residual | Chi square | |
Category | frequency(p) | Oi | Ei=total*p | R2i=(Oi-Ei)/√Ei | R2i=(Oi-Ei)2/Ei |
At home | 0.3400 | 389 | 406.70 | -17.7000 | 0.77 |
At work | 0.1700 | 110 | 98.77 | 11.2300 | 1.28 |
During Commute | 0.0800 | 55 | 46.48 | 8.5200 | 1.56 |
Coffee Shop | 0.0500 | 27 | 29.05 | -2.0500 | 0.14 |
total | 0.64 | 581 | 581 | 1.77636E-14 | 3.75 |
test statistic X2= | 3.7536 | ||||
p value = | 0.2893 | from excel: chidist(3.754,3) |
since p value >0.05
A.Do not reject Ho
A. The data is a good fit.
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