Answer:
For sample distribution to be assumed as approximately normal, the conditions are
(a) np 5
(b) n(1-p) 5
here, n = 30
p = 0.90
np = 30x0.9 = 27
n(1-p) = 30x(1-0.9) = 3
n(1-p) < 5. Condition (b) is not satisfied here
So, we cannot assume the sample distribution is normally distributed
it is False
NOTE:: I HOPE YOUR HAPPY WITH MY ANSWER....***PLEASE SUPPORT ME WITH YOUR RATING...
***PLEASE GIVE ME "LIKE"...ITS VERY IMPORTANT FOR ME NOW....PLEASE SUPPORT ME ....THANK YOU
Get Answers For Free
Most questions answered within 1 hours.