Question

Fill in the blanks. The depth of the snow in my yard is normally distributed, with...

Fill in the blanks. The depth of the snow in my yard is normally distributed, with a mean of 2.5 inches and a standard deviation of 0.25 inches. What value is one standard deviation below the mean? inches What value is one standard deviation above the mean? inches What is the probability that a randomly chosen location will have a snow depth between 2.25 and 2.75 inches? percent

Homework Answers

Answer #1

1 standard deviation below the mean = mean - 1 * SD

= 2.5 - 1 * 0.25

= 2.25

1 standard deviation above the mean = mean + 1 * SD

= 2.5 + 1 * 0.25

= 2.75

P ( 2.25 < X < 2.75 ) = ?
Standardizing the value
Z = ( X - µ ) / σ
Z = ( 2.25 - 2.5 ) / 0.25
Z = -1
Z = ( 2.75 - 2.5 ) / 0.25
Z = 1
P ( -1 < Z < 1 ) =  P ( 2.25 < X < 2.75 ) = P ( Z < 1 ) - P ( Z < -1 )
P ( 2.25 < X < 2.75 ) = 0.8413 - 0.1587
P ( 2.25 < X < 2.75 ) = 0.6827

= 68.27%

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