A confidence interval is desired for the true average sale volume. Assume that the population standard deviation is known to be 3. How large a random sample is needed to construct a 99% interval for the true average sale volume with a margin of error equal to 1?
Solution :
Given that,
Population standard deviation = = 3
Margin of error = E = 1
At 99% confidence level the z is,
= 1 - 99%
= 1 - 0.99 = 0.01
/2 = 0.005
Z/2 = Z 0.005 = 2.576
sample size = n = [Z/2* / E] 2
n = [2.576 * 3 / 1 ]2
n = 59.72
Sample size = n = 60
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