Question

the probability of chester making a free throw in the championship basketball game is 80% and each throw is independent of his last throw. assume that chester attempts five throws during the game. what is the probability that he will make less than two of his free throws durinf the game? round three decimal places

Answer 1

solution:

probability of free throw = p = 80% = 0.8

attempting throws = n = 5

we have to find the probabilty that the less than the two free throws = P(X <2)

it is given that the each throw is independent of each other. so using binomial distribution formula as folows:

P(X <2) = P(X = 0) + P(X = 1)

P(X <2 ) = 0.0003 + 0.0064 = 0.0067 = 0.007             (rounding to three decimal)