A coin is tossed 5 times.
What is the probability of getting all heads? Express your answer as a simplified fraction or a decimal rounded to four decimal places.
Let X = Number of heads in 5 trials. Thus possible values of X are 0,1,2,3,4,5
p = probability of getting head = 0.5
n = number of trial = 5
X follows binomial distribution with parameter n and p. PMF of X is
Now we find probability of getting zero heads.
Similarly we find all probabilies.
Probability distribution of X is,
X | 0 | 1 | 2 | 3 | 4 | 5 |
P(X) | 0.0312 | 0.1562 | 0.3125 | 0.3125 | 0.1562 | 0.0312 |
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