Heights of adult males are approximately normally distributed with a mean of 66.6 inches and a standard deviation of 1.9 inches. If a sample of 50 adult males are chosen, what is the probability their mean height will be between 67 inches and 67.4 inches? Report your answer to four decimal places.
Solution :
= / n = 1.9 / 50 = 0.2687
= P[(67 - 66.6) / 0.2687 < ( - ) / < (67.4 - 66.6) / 0.2687)]
= P(1.49 < Z < 2.98)
= P(Z < 2.98) - P(Z < 1.49)
= 0.9986 - 0.9319
= 0.0667
Probability = 0.0667
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