Question

A survey found that​ women's heights are normally distributed with mean 63.4 in. and standard deviation 2.4 in. The survey also found that​ men's heights are normally distributed with a mean 67.5 in. and standard deviation 2.7.

a)Most of the live characters at an amusement park have height requirements with a minimum of 4 ft 8 in. and a maximum of 6 ft 2 in. Find the percentage of women meeting the height requirement. The percentage of women who meet the height requirement is

b)Find the percentage of men meeting the height requirement. The percentage of men who meet the height requirement is nothing

Answer 1

	Women	Men
µ	63.4	67.5
σ	2.4	2.7

1ft= 12 in

Height requirements are

Minimum = 4 ft 8 in = 48+8=56 in ( 4 ft = 4 * 12= 48 in)

Maximum = 6ft 2 in =72+2= 74 in (6ft = 6*12 = 72 in)

a)

We will use Ti 83/84

Press 2ND...VARS...normalcdf

Enter values as

Result is

The percentage of women who meet the height requirement is 99.9830343 %

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b)

Press 2ND...VARS...normalcdf

Enter values as

result is

The percentage of men who meet the height requirement is 95.22096696 %