A programmer plans to develop a new software system. In planning for the operating system that he will use, he needs to estimate the percentage of computers that use a new operating system. How many computers must be surveyed in order to be 95% confident that his estimate is in error by no more than five percentage points question mark Complete parts (a) through (c) below.
ANSWER:
Given that,
= 0.5
1 - = 1 - 0.5 = 0.5
Margin of error = E = 4% = 0.04
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96
Sample size = ( Z/2 / E)2 * * (1 - )
= (1.96 / 0.04)2 * 0.5 * 0.5
= 600.25
Sample size = n =601
601 computers must be surveyed .
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