Question

55 people are randomly selected and the accuracy of their wristwatches is checked, with positive errors...

55 people are randomly selected and the accuracy of their wristwatches is checked, with positive errors representing watches that are ahead of the correct time and negative errors representing watches that are behind the correct time. The 55 values have a mean of 106sec and a standard deviation of 216sec. Use a 0.02 significance level to test the claim that the population of all watches has a mean of 0sec.

The test statistic is ?

The P-Value is ?

Homework Answers

Answer #1

------------------------------------------

t = 3.639

p-value = 0.0006

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
45 people are randomly selected and the accuracy of their wristwatches is checked, with positive errors...
45 people are randomly selected and the accuracy of their wristwatches is checked, with positive errors representing watches that are ahead of the correct time and negative errors representing watches that are behind the correct time. The 45 values have a mean of 111sec and a standard deviation of 247 sec. Use a 0.02 significance level to test the claim that the population of all watches has a mean of 0sec. The test statistic is The P-Value is
40 people are randomly selected and the accuracy of their wristwatches is checked, with positive errors...
40 people are randomly selected and the accuracy of their wristwatches is checked, with positive errors representing watches that are ahead of the correct time and negative errors representing watches that are behind the correct time. The 40 values have a mean of 51 sec and a standard deviation of 188 sec. Use a 0.02 significance level to test the claim that the population of all watches has a mean of 0 sec. (Assume σ=188 sec.) (a) The test statistic...
45 people are randomly selected and the accuracy of their wristwatches is checked, with positive errors...
45 people are randomly selected and the accuracy of their wristwatches is checked, with positive errors representing watches that are ahead of the correct time and negative errors representing watches that are behind the correct time. The 45 values have a mean of 98sec and a standard deviation of 192sec. Use a 0.01 significance level to test the claim that the population of all watches has a mean of 0sec. The test statistic is The P-Value is The final conclustion...
4040 people are randomly selected and the accuracy of their wristwatches is checked, with positive errors...
4040 people are randomly selected and the accuracy of their wristwatches is checked, with positive errors representing watches that are ahead of the correct time and negative errors representing watches that are behind the correct time. The 4040 values have a mean of 9191sec and a standard deviation of 174174sec. Use a 0.020.02 significance level to test the claim that the population of all watches has a mean of 00sec. The test statistic is The P-Value is The final conclustion...
5050 people are randomly selected and the accuracy of their wristwatches is checked, with positive errors...
5050 people are randomly selected and the accuracy of their wristwatches is checked, with positive errors representing watches that are ahead of the correct time and negative errors representing watches that are behind the correct time. The 5050 values have a mean of 115115sec and a standard deviation of 177177sec. Use a 0.020.02 significance level to test the claim that the population of all watches has a mean of 00sec. The test statistic is The P-Value is The final conclustion...
(1 point) 5555 people are randomly selected and the accuracy of their wristwatches is checked, with...
(1 point) 5555 people are randomly selected and the accuracy of their wristwatches is checked, with positive errors representing watches that are ahead of the correct time and negative errors representing watches that are behind the correct time. The 5555 values have a mean of 119119sec and a population standard deviation of 155155sec. Use a 0.010.01 significance level to test the claim that the population of all watches has a mean of 00sec (use a two-sided alternative). The test statistic...
(1 pt) 50 people are randomly selected and the accuracy of their wristwatches is checked, with...
(1 pt) 50 people are randomly selected and the accuracy of their wristwatches is checked, with positive errors representing watches that are ahead of the correct time and negative errors representing watches that are behind the correct time. The 50 values have a mean of 75 sec and a standard deviation of 234 sec. Use a 0.02 significance level to test the claim that the population of all watches has a mean of 0 sec. (Assume σ=234 sec.) (a) The...
(1 point) A random sample of 100 observations from a population with standard deviation 25.11 yielded...
(1 point) A random sample of 100 observations from a population with standard deviation 25.11 yielded a sample mean of 94.2 1. Given that the null hypothesis is ?=90and the alternative hypothesis is ?>90 using ?=.05, find the following: (a) Test statistic = (b) P - value: (c) The conclusion for this test is: _____A. There is insufficient evidence to reject the null hypothesis ______B. Reject the null hypothesis ______C. None of the above 2. Given that the null hypothesis...
4) 25 randomly selected people were surveyed and it was found that the average amount they...
4) 25 randomly selected people were surveyed and it was found that the average amount they charged was 1200 in a year with a standard deviation of 600. Given α = 0.025, test the claim that the mean amount charged by all people with credit cards is greater than 1300. Confirm your results using the p–value method as well as the critical t value. 5) 5) In a study 800 people out of 1000 people surveyed indicated that they supported...
Randomly selected 2020 student cars (population 1) have ages with a mean of 77 years and...
Randomly selected 2020 student cars (population 1) have ages with a mean of 77 years and a standard deviation of 3.63.6 years, while randomly selected 2222 faculty cars (population 2) have ages with a mean of 55 years and a standard deviation of 3.73.7 years. (For the purposes of this exercise, the two populations are assumed to be normally distributed.) 1.    Use a 0.030.03 significance level to test the claim that student cars are older than faculty cars. The test statistic...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT