2. A 90% confidence interval for the mean percentage of airline reservations being canceled on the day of the flight is (1.1%, 3.2%). What is the point estimator of the sample mean of reservations that are canceled on the day of the flight?
3. A 90 % confidence interval for the mean percentage of airline reservations being canceled on the day of the flight is (1.1%, 3.2%). What is the margin of error of this confidence interval?
Solution :
2) = (Lower confidence interval + Upper confidence interval ) / 2
Sample mean = = (1.1% + 3.2%) / 2
Sample mean = = 2.15%
correct option is = b
3) Margin of error = E = Upper confidence interval -
Margin of error = E = 3.2% - 2.15%
Margin of error = E = 1.05%
correct option is = d
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