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Let X denote the distance (m) that an animal moves from its birth site to the...

Let X denote the distance (m) that an animal moves from its birth site to the first territorial vacancy it encounters. Suppose that for banner-tailed kangaroo rats, X has an exponential distribution with parameter λ = 0.01447. What is the probability that the distance is at most 100 m?(Round your answer to four decimal places.)

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Answer #1

Given that, X has an exponential distribution with parameter  λ = 0.01447.

We want to find, P(X ≤ 100)

Therefore, required probability is 0.7647

Note : Using Excel we find this probability as follows :

Excel Command: =EXPONDIST(100,0.01447,1) = 0.7647

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