You wish to test the following claim (HaHa) at a significance
level of α=0.005α=0.005.
Ho:μ=77.1Ho:μ=77.1
Ha:μ<77.1Ha:μ<77.1
You believe the population is normally distributed, but you do not
know the standard deviation. You obtain a sample of size n=9n=9
with mean M=58.9M=58.9 and a standard deviation of
SD=13.3SD=13.3.
What is the test statistic for this sample? (Report answer accurate
to three decimal places.)
test statistic =
What is the p-value for this sample? (Report answer accurate to
four decimal places.)
p-value =
The p-value is...
This test statistic leads to a decision to...
As such, the final conclusion is that...
Since the population distribution is normal and we do not know the standard deviation, we will use the t-statistic here, which is given as
t= (xbar- mean)/ S/ sqrt(n)
where xbar= sample mean, mean= population mean, S= sample standard deviation, n= sample size
Now, t= (58.9- 77.1)/13.3/ sqrt(9)
= -18.2* sqrt(9)/13.3= -18.2* 3/ 13.3
= -54.6/13.3= -4.1052631579= -4.105 (upto three decimal places)
Again p-value for this t-score with left-tailed test ( since Ha: mean< 77.1) and n-1= 8 degrees of freedom, is given as 0.00170706= 0.0017( upto 4 decimal places)
Now, we see that the p-value= 0.0017 is less than alpha= 0.005.
Now, since the p-value is less than alpha, we will reject the null hypothesis and conclude that the test is Statistically significant.
The final conclusion will be that the sample data support the claim that the population mean is less than 77.1
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