The correct size of a nickel is 21.21 millimeters. Based on
that, the data can be summarized into the following
table:
Too Small | Too Large | Total | |
---|---|---|---|
Low Income | 18 | 22 | 40 |
High Income | 19 | 16 | 35 |
Total | 37 | 38 | 75 |
For children in the low income group, find a
90% confidence interval for the proportion of children that drew
the nickel too large.
Give all answers correct to 3 decimal places.
a) Critical value (positive value only): Correct
b) Margin of error: .129Correct
c) Confidence interval: .421 < pp < .679 ? not sure if this
is correct?
d) Does the confidence interval support the claim that more than
40% of children from the low income group draw nickels too
large?
n = 40, x = 22
p̂ = x/n = 0.55
a) At α = 0.1, two tailed critical value, z_c = NORM.S.INV(0.1/2) = 1.645
b) Margin of error, E = z*√(p̂ *(1- p̂)/n) =1.645 *√(0.55*0.45/40) = 0.129
c) 90% Confidence interval :
Lower Bound = p̄ - E = 0.55 - 0.129 = 0.421
Upper Bound = p̄ + E = 0.55 + 0.129 = 0.679
0.421 < p < 0.679
d) As the confidence interval do not contain 0.40 and both the values are greater than 0.40 so we can reject the null hypothesis.
Confidence interval supports claim.
Get Answers For Free
Most questions answered within 1 hours.