Find the χ2 critical values
a. χ2 (20, .025)
b. χ2 (2, .05)
c. χ2 (18, 10)
d. χ2 (16, .95)
e. χ2 (30, .90)
f. χ2 (80, .995)
Solution:-
a) χ2 (20, .025)
n = 20
df = n-1 = 20 -1 = 19
= 0.025
χ2 = 32.85
b) n = 2
df = n-1 = 2 -1 = 1
= 0.05
χ2 = 3.84
c) n = 18
df = n-1 =18 -1 = 17
= 0.10
χ2 =24.77
d) n = 16
df = n-1 =16 -1 = 15
= 0.95
χ2 = 7.26
e) n = 30
df = n-1 =30 -1 = 29
= 0.90
χ2 = 19.77
f) n = 80
df = n-1 =80 -1 = 79
= 0.995
χ2 = 50.38
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