The test statistic t = ()/(s/)
= (17.5 - 10)/(1/sqrt(20))
= 33.54
At = 0.01, the critical value t0.01, 19 = -2.539
Since the test statistic value is not less than the lower critical value (33.54 > -2.539), we should not reject H0.
Get Answers For Free
Most questions answered within 1 hours.