Question

When 20 campers are randomly selected and surveyed, it was found that the average number that...

When 20 campers are randomly selected and surveyed, it was found that the average number that prefer to camp at the beach was 77. Assume the population standard deviation is 13.2. Construct a 90% confidence interval for the true population mean of the number of campers who prefer to camp at the beach.

Give your answers to 2 decimal places.
Error =
< μμ <

Homework Answers

Answer #1

We have given that,          
          
Sample mean =77  
Population standard deviation=   13.2
Sample size=20  
Level of significance =1-0.90=0.1  
Z critical value (by using Z table)=1.645  

Margin of error

E=4.86


Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
when 294 college students are randomly selected and surveyed, it is found that 130 own a...
when 294 college students are randomly selected and surveyed, it is found that 130 own a car. Find a 90% confidence interval for the proportion of all college students who own a car. Show all work!!
The thicknesses of 20 randomly selected linoleum tiles were found to have a standard deviation of...
The thicknesses of 20 randomly selected linoleum tiles were found to have a standard deviation of 2.66 Construct the 95% confidence interval for the population standard deviation of the thicknesses of all linoleum tiles in this factory. Round your answers to two decimal places.
The thicknesses of 13 randomly selected linoleum tiles were found to have a standard deviation of...
The thicknesses of 13 randomly selected linoleum tiles were found to have a standard deviation of 4.76. Construct the 90% confidence interval for the population standard deviation of the thicknesses of all linoleum tiles in this factory. Round your answers to two decimal places.
A hair salon in Cambridge, Massachusetts, reports that on seven randomly selected weekdays, the number of...
A hair salon in Cambridge, Massachusetts, reports that on seven randomly selected weekdays, the number of customers who visited the salon were 72, 55, 49, 35, 39, 23, and 77. It can be assumed that weekday customer visits follow a normal distribution. [You may find it useful to reference the t table.] a. Construct the 90% confidence interval for the average number of customers who visit the salon on weekdays. (Round intermediate calculations to at least 4 decimal places, "sample...
A survey of 25 randomly selected customers found that their average age was 31.84 years with...
A survey of 25 randomly selected customers found that their average age was 31.84 years with a standard deviation of 9.84 years. What is the standard error of the mean? How would the standard error have changed if the sample size had been 100 instead of 25 (assuming that the mean and standard deviations were the same)? How many degrees of freedom would the t-statistic have for this set of data? What would the critical value t* be for a...
1.) A randomly selected sample of 70 casino patrons has an average loss of $300 with...
1.) A randomly selected sample of 70 casino patrons has an average loss of $300 with a sample standard deviation of $100. Use this information to complete the following: a) Does the information above provide an estimate of a population mean or a population proportion? b) Provide a point estimate for the population mean loss of all casino patrons. c) Construct and interpret a 90% confidence interval for the parameter you selected in part (a). d) What is the margin...
A survey of 25 randomly selected customers found the ages shown​ (in years). The mean is...
A survey of 25 randomly selected customers found the ages shown​ (in years). The mean is 32.88 years and the standard deviation is 8.96 years. ​a) Construct a 90​% confidence interval for the mean age of all​ customers, assuming that the assumptions and conditions for the confidence interval have been met. ​b) How large is the margin of​ error? ​c) How would the confidence interval change if you had assumed that the standard deviation was known to be 9.0 ​years?
A sample of 105 laramie residents was randomly selected and surveyed about Easter weekend spending. Their...
A sample of 105 laramie residents was randomly selected and surveyed about Easter weekend spending. Their 95% confidence interval for the true average amount of money that Laramie residents spend during the Easter weekend was calculated to be $277< μ < $327. National data shows that the standard deviation of money spent duing easter weekend is $91.00. a.) What is the error? b.) If I wanted to calculate a new confidence interval and drop my error to $12.00, how large...
Suppose the marketing company did do a survey. They randomly surveyed 200 households and found that...
Suppose the marketing company did do a survey. They randomly surveyed 200 households and found that in 120 of them, the woman made the majority of the purchasing decisions. We are interested in the population proportion of households where women make the majority of the purchasing Construct a 95% confidence interval for the population proportion of households where the women make the majority of the purchasing decisions. State the confidence interval, sketch the graph and calculate the error bound.
A survey of 100 randomly selected Michigan residents finds that the they spend a mean of...
A survey of 100 randomly selected Michigan residents finds that the they spend a mean of $21 per month on going to the movies. An independent study of a 100 randomly selected California residents find that they spend a mean of $46 per month on going to the movies. Assume that the population standard deviation for the Michigan residents is $5 per month and that the population standard deviation for the California residents is $23 per month. Answer the following...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT