The table below presents three samples of data. If we conduct a hypothesis test for the equality of all three means with the statistical confidence of 90%, what would the value of the Mean Squares Between Groups be?
Sample 1 |
Sample 2 | Sample 3 |
7 | 11 | 6 |
5 | 8 | 5 |
7 | 11 | 4 |
6 | 7 | 5 |
6 | 13 | 14 |
6 | 13 | 5 |
6 | 12 | 5 |
6 | 11 | 6 |
8 | 8 | 8 |
9 | 7 | 6 |
7 | 6 | 14 |
9 | 7 | 4 |
8 | 8 | 8 |
8 | 9 | 13 |
9 | 6 | 10 |
8 | 11 | 14 |
8 | 9 | 14 |
9 | 12 | 8 |
6 | 11 | |
8 | 12 | |
12 | 9 | |
11 | 5 |
For the given data using Anova single factor in Excel we get output as
Anova: Single Factor | ||||||
SUMMARY | ||||||
Groups | Count | Sum | Average | Variance | ||
Sample 1 | 22 | 169 | 7.681818 | 2.989177 | ||
Sample 2 | 22 | 206 | 9.363636 | 5.95671 | ||
Sample 3 | 18 | 149 | 8.277778 | 14.80065 | ||
ANOVA | ||||||
Source of Variation | SS | df | MS | F | P-value | F crit |
Between Groups | 31.88009 | 2 | 15.94005 | 2.13997 | 0.126703 | 2.394832 |
Within Groups | 439.4747 | 59 | 7.448725 | |||
Total | 471.3548 | 61 |
So from the above output
Mean Squares Between Groups = 15.94005
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