Question

A random sample of 130 mortgages in the state of California was randomly selected. From this...

A random sample of 130 mortgages in the state of California was randomly selected.
From this sample, 14 were found to be delinquent on their current payment. The 98%
confidence interval for the proportion based on this sample is ________.
a) (0.015, 0.201)
b) (0.029, 0.188)
c) (0.036, 0.280)
d) (0.044, 0.172)

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
when 294 college students are randomly selected and surveyed, it is found that 130 own a...
when 294 college students are randomly selected and surveyed, it is found that 130 own a car. Find a 90% confidence interval for the proportion of all college students who own a car. Show all work!!
A random sample of n1 = 288 voters registered in the state of California showed that...
A random sample of n1 = 288 voters registered in the state of California showed that 147 voted in the last general election. A random sample of n2 = 217 registered voters in the state of Colorado showed that 130 voted in the most recent general election. Do these data indicate that the population proportion of voter turnout in Colorado is higher than that in California? Use a 5% level of significance. What is the test statistic? Find the P-Value
Fifteen out of the 145 randomly selected study-abroad students who were surveyed in a state can...
Fifteen out of the 145 randomly selected study-abroad students who were surveyed in a state can speak the French language. Construct and interpret a 98% confidence interval for the proportion of all study-abroad students in the state who can speak French.
Suppose you have selected a random sample of ?=14 measurements from a normal distribution. Compare the...
Suppose you have selected a random sample of ?=14 measurements from a normal distribution. Compare the standard normal ? values with the corresponding ? values if you were forming the following confidence intervals. (a)    90% confidence interval z= t= (b)    95% confidence interval z=   t= (c)    98% confidence interval ?= t= 2) A confidence interval for a population mean has length 20. a) Determine the margin of error. b) If the sample mean is 58.6, obtain the confidence interval. Confidence interval: ( ,...
A random sample of 130 adult males was selected as part of a study on weight...
A random sample of 130 adult males was selected as part of a study on weight loss. The average weight at the beginning of the study was 265 pounds with a standard deviation of 22 pounds. Assuming the weight is normally distributed, provide a 99% confidence interval for the mean weight at the start of the study. You MUST show your work to receive full credit.
In a sample of 160 children selected randomly from one town, it is found that 35...
In a sample of 160 children selected randomly from one town, it is found that 35 of them suffer from asthma. a) Construct a 99% confidence interval. b) At the 0.05 significance level, test the claim that the proportion of all children in the town who suffer from asthma is 11%.
In a simple random sample of 70 automobiles registered in a certain state, 24 of them...
In a simple random sample of 70 automobiles registered in a certain state, 24 of them were found to have emission levels that exceed a state standard. What proportion of the automobiles in the sample had emission levels that exceed the standard? Round the answer to two decimal places. Find a 95% confidence interval for the proportion of automobiles in the state whose emission levels exceed the standard. Round the answers to three decimal places. Find a 98% confidence interval...
A random sample of elementary school children in New York state is to be selected to...
A random sample of elementary school children in New York state is to be selected to estimate the proportion p who have received a medical examination during the past year. It is desired that the sample proportion be within 0.02 of the true proportion with a 98% level of confidence, (Be sure to use four or five decimals of accuracy for all values used in the calculations, including the z-score) (a) Assuming no prior information about p is available, approximately...
From a large number of actuarial scores, a random sample of 250 scores is selected, and...
From a large number of actuarial scores, a random sample of 250 scores is selected, and it is found that 177 of these are passing scores. Based on this sample, find a 90% confidence interval for the proportion of all scores that are passing. Then complete the table below. Carry your intermediate computations to at least three decimal places. Round your answers to two decimal places. What is the lower limit of the 90% confidence interval?____ What is the upper...
In a randomly selected sample of 500 registered voters in a community, 240 individuals say that...
In a randomly selected sample of 500 registered voters in a community, 240 individuals say that they plan to vote for Candidate Y in the upcoming election. Find a 95% confidence interval for the proportion of the registered voter population who plan to vote for Candidate Y. (Round your answers to three decimal places.) Find a 98% confidence interval for the proportion of the registered voter population who plan to vote for Candidate Y. (Round your answers to three decimal...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT