For this problem, carry at least four digits after the decimal
in your calculations. Answers may vary slightly due to
rounding.
In a random sample of 70 professional actors, it was found that 39
were extroverts.
(a) Let p represent the proportion of all actors who
are extroverts. Find a point estimate for p. (Round your
answer to four decimal places.)
(b) Find a 95% confidence interval for p. (Round your
answers to two decimal places.)
lower limit | |
upper limit |
Solution :
Given that,
(a)
Point estimate = sample proportion = = x / n = 39 / 70 = 0.557
1 - = 0.43
Z/2 = 1.96
(b)
Margin of error = E = Z / 2 * (( * (1 - )) / n)
= 1.96 * (((0.557 * 0.443) / 70)
= 0.12
A 95% confidence interval for population proportion p is ,
- E < p < + E
0.557 - 0.12 < p < 0.557 + 0.12
0.44 < p < 0.67
Lower limit = 0.44
Upper limit = 0.67
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