In a survey, 15 people were asked how much they spent on their
child's last birthday gift. The results were roughly bell-shaped
with a mean of $35 and standard deviation of $20. Construct a
confidence interval at a 98% confidence level.
Give your answers to one decimal place.
Sample size n = 15
Sample mean Xbar = $ 35
Sample standard deviation s = $ 20
The 98% confidence interval for population mean
xbar - E < < xbar + E
Where E = ta/2*( s/√n)
For a = 0.02 and d.f = n -1 = 14
ta/2 , n -1 = t0.01 , 14
Using t table
t0.01,14 = 2.624
E = 2.624*(20/√15)
E = 13.55
35 - 13.55 < < 35 + 13.55
21.4 < < 48.6
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