A random variable X is normally distributed. Suppose we obtain a random sample of 11 elements from the population. Further assume that the population variance is 100. Find the probability that the sample variance is at least 48.6.
The random variable x is normally distributed.
The sample size is n=11
Population variance is = 100
Calculate the probability that the sample varance is at least 48.6
P(s2 48.6) = 1- P (s248.6)
= 1 - P
= 1- P
= 1-P(X24.86)(From chi-square table)
= 1-0.09967
=0.90
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