Question

Of 400 students, 150 are male students and 250 are female students, 60 of the male...

Of 400 students, 150 are male students and 250 are female students, 60 of the male students and 90 of the female students fail the statistics course. A student is selected at random from these 400 students. What is the probability that the selected student would be a male or fail the statistics course?

Select one:

a. 0.525

b. 0.15

c. 0.75

d. 0.6

A prospective developer of a shopping mall in an area believes that the average annual income per capita in the area is $280,000. Historical data suggest that for the type of area involved, household incomes per capita are skewed. The population standard deviation can be accepted as being equal to $22,000, based on an earlier study. The prospective developer wants to estimate the true mean annual income per capita in the area. For a random sample of 25 individuals, the mean annual income is found to be $265,000. Using the 95% confidence level, what is the interval estimate of the true mean income per capita in the area?

Select one:

a. $255,918.84 to $274,081.16

b. No solution

c. $256,376 to $273,624

d. $271,376 to $288,624

Homework Answers

Answer #1

Q 1

fail pass Total
male 60 90 150
female 90 160 250
Total 150 250 400

P(male or fail) = P (male) + P (fail) - P(male and fail) = 150/ 400 + 150/400 - 60/400 = 240 / 400 = 0.60

ANS: Probability that the selected student would be a male or fail the statistics course = 0.60

Q 2

n = 25

= 22000

sample mean = 265000

z value for 95% CI = 1.960

CI = mean + /- E

CI = 265000 +/ - 8624

CI = 256376 , 273624

ANS: Option c. $256,376 to $273,624

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