Of 400 students, 150 are male students and 250 are female students, 60 of the male students and 90 of the female students fail the statistics course. A student is selected at random from these 400 students. What is the probability that the selected student would be a male or fail the statistics course?
Select one:
a. 0.525
b. 0.15
c. 0.75
d. 0.6
A prospective developer of a shopping mall in an area believes that the average annual income per capita in the area is $280,000. Historical data suggest that for the type of area involved, household incomes per capita are skewed. The population standard deviation can be accepted as being equal to $22,000, based on an earlier study. The prospective developer wants to estimate the true mean annual income per capita in the area. For a random sample of 25 individuals, the mean annual income is found to be $265,000. Using the 95% confidence level, what is the interval estimate of the true mean income per capita in the area?
Select one:
a. $255,918.84 to $274,081.16
b. No solution
c. $256,376 to $273,624
d. $271,376 to $288,624
Q 1
fail | pass | Total | |
male | 60 | 90 | 150 |
female | 90 | 160 | 250 |
Total | 150 | 250 | 400 |
P(male or fail) = P (male) + P (fail) - P(male and fail) = 150/ 400 + 150/400 - 60/400 = 240 / 400 = 0.60
ANS: Probability that the selected student would be a male or fail the statistics course = 0.60
Q 2
n = 25
= 22000
sample mean = 265000
z value for 95% CI = 1.960
CI = mean + /- E
CI = 265000 +/ - 8624
CI = 256376 , 273624
ANS: Option c. $256,376 to $273,624
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