The following data represent the high-temperature distribution for a summer month in a city for some of the last 130 years. Treat the data as a population. Complete parts (a) through (c).
Temperature: 50-59 60-69 70-79 80-89 90-99 100-109
Days: 2 306 1470 1529 311 9
mean = ___________
standard deviation = _______________
(b) Use the frequency histogram of the data to verify that the distribution is bell shaped.
____ No, the frequency histogram of the data is not bell shaped.
____ Yes, the frequency histogram of the data is bell shaped.
(c) According to the empirical rule, 95% of days in the month will be between what two temperatures?
______ and ______
x | f | f*m | f*m2 |
54.5 | 2 | 109 | 5940.5 |
64.5 | 306 | 19737 | 1273036.5 |
74.5 | 1470 | 109515 | 8158867.5 |
84.5 | 1529 | 129200.5 | 10917442 |
94.5 | 311 | 29389.5 | 2777307.8 |
104.5 | 9 | 940.5 | 98282.25 |
total | 3627 | 288891.5 | 23230877 |
mean =x̅=Σf*M/Σf= | 79.650 | ||
Variance σ2=(ΣfM2-(ΣfM)2/n)/n= | 60.82 | ||
Std deviation σ= | √σ2 = | 7.799 |
from above:
mean =79.65
standard deviation =7.80
b)
Yes, the frequency histogram of the data is bell shaped.
c)
since from empirical rule, 95% of days are 2 standard deviation from the mean value:
95% interval values = 79.65 -/+ 2*7.80 = 64.05 and 95.25
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