A department store manager has monitored the number of complaints received per week about poor service. The probabilities for numbers of complaints in a week, established by this review, are shown in the table.
Number of complaints | 0 | 1 | 2 | 3 | 4 | 5 |
---|---|---|---|---|---|---|
Probability | 0.15 | 0.20 | 0.41 | 0.11 | 0.06 | 0.07 |
What is the mean of complaints received per week?
Please round your answer to the nearest hundredth.
Note that the correct answer will be evaluated based on the full-precision result you would obtain using Excel.
the necessary calculation table:-
number of complaints(x) | P(x) | x*P(x) |
0 | 0.15 | 0 |
1 | 0.2 | 0.2 |
2 | 0.41 | 0.82 |
3 | 0.11 | 0.33 |
4 | 0.06 | 0.24 |
5 | 0.07 | 0.35 |
sum = 1.94 |
[ i have used excel to calculate the third column, i.e, x*P(x) and the sum of that column by using =SUM function in excel ]
the mean of complaints received per week is :-
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