Given the sample results taken from a normal population distribution: mean = 4.65, σ = 0.32, and n = 13. Find the margin-of-error and the 95% confidence interval for the population mean. (use 2 decimal places)
Solution :
Given that,
Population standard deviation = = 0.32
Sample size n =13
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96 ( Using z table )
Margin of error = E = Z/2
* (
/n)
=1.96 * (0.32 / 13)
E= 0.17
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