MEDICATION ‘’A’’: | 5 | 7 | 4 | 9 | 5 | 7 | 6 | 6 | 9 | 8 | ||
MEDICATION ‘’B’’: | 3 | 2 | 4 | 5 | 4 | 4 | 3 | 5 | 3 |
4 |
The SQRT(1/nA + 1/nB) = SQRT ( 1/10 + 1/10) = SQRT (0.2) = __________ | ||||||||||||
The 95% CI is therefore (MA – MB) ± t α/2 * Sp * SQRT(1/nA + 1/nB) = ______ ± _____ = _____<M<_____. |
The data is given by:-
MEDICATION ‘’A’’: | MEDICATION ‘’B’’: | |
5 | 3 | |
7 | 2 | |
4 | 4 | |
9 | 5 | |
5 | 4 | |
7 | 4 | |
6 | 3 | |
6 | 5 | |
9 | 3 | |
8 | 4 | |
Count | 10 | 10 |
Mean | 6.6 | 3.7 |
StDev | 1.712697677 | 0.948683298 |
The SQRT(1/nA + 1/nB) = SQRT ( 1/10 + 1/10) = SQRT (0.2) = 0.4472
The critical value for α=0.05 and df=18 degrees of freedom is
We need to compute the pooled standard deviation, as follows:
The standard error is computed as follows:
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