_________% of the scores fall between a z-score of -1.00 and a z-score of +2.00
17.89 |
||
81.85 |
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48.32 |
||
65.17 |
We have to find the percentage of the scores that fall between a z-score of -1.00 and a z-score of +2.00.
So, first we find the probability that a randomly selected score falls between z=-1.00 and z=2.00.
So, we find
Where, phi is the distribution function of the standard normal variate.
From the standard normal table, this becomes
So, the corresponding percentage is 0.8185*100, ie. 81.85%.
So, the correct answer is option (b) 81.85%.
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