Question

1. Write up your report based on the t-test finding using the appropriate template below (depending on your t-test finding – you should choose the appropriate template below): (4 points)
   

1. Use this template if your result is Significant

There was a significant difference in the levels of intention to purchase Mochamania versus Iceemania, t(39) = 5.43, p < .001 [plug in appropriate numbers from your test result], with Mochamania (mean = xxx, S.D. = yyy) receiving a higher level of purchase intention than Iceemania (mean = xxx, S.D. = yyy).

2. Use this template if your result is NOT Significant.

There was no significant difference in the levels of intention to purchase Mochamania (mean = xxx, S.D. = yyy) versus Iceemania (mean = xxx, S.D. = yyy), t(39) = .089, p = .88 [plug in appropriate numbers from your test result].

Paired Samples Statistics
		Mean	N	Std. Deviation	Std. Error Mean
Pair 1	M: Participant's intention to purchase the new Mochamania product	4.15	40	2.949	.466
	I: Participant's intention to purchase the new Iceemania product	4.15	40	1.122	.177

Paired Samples Correlations
		N	Correlation	Sig.
Pair 1	M: Participant's intention to purchase the new Mochamania product & I: Participant's intention to purchase the new Iceemania product	40	-.449	.004

Paired Samples Test
		Paired Differences					t	df	Sig. (2-tailed)
		Mean	Std. Deviation	Std. Error Mean	95% Confidence Interval of the Difference
					Lower	Upper
Pair 1	M: Participant's intention to purchase the new Mochamania product - I: Participant's intention to purchase the new Iceemania product	.000	3.595	.568	-1.150	1.150	.000	39	1.000

Answer 1

Paired sample test compares the mean of two dependent samples.According to the t test the results are not significant as the p value is 1>.001.So the result is insignificant at 0.1% significance level. Hence the conclusion based on the paired sample test would be

"There was no significant difference in the levels of intention to purchase Mochamania (mean = 4.15, S.D. =2.949) versus Iceemania (mean = 4.15, S.D. =1.122), t(39) = 0, p = 1."

A correlation test was also performed for the samples.

The pvalue(0.004)>0.001. Hence the result is again not significant at 0.1% significance level. But it is significant for 1% significance level. So at 1% we can conclude that there exist a negative correlation between the variables.