Question

HW 9

Assume that a 90% confidence interval for a population proportion has lower bound = 0.24 and upper bound = 0.34.

*The sample proportion based on the collected data is                            [ Select ]                       ["0.29", "unknown", "0.34", "0.24"]      

*The margin of error is                            [ Select ]                       ["0.025", "0.010", "0.05", "0.10"]      

*α/2α/2 for this confidence interval is                            [ Select ]                       ["0.005", "0.001", "0.05", "0.025"]      

Answer 1

Sol:

sample proprtion-margin of error=0.24--->(1)

sample proportion+margin of error=0.34 ----->(2)

add 2 equations

2p^=0.24+0.34

p^=0.29

*The sample proportion based on the collected data is 0.29

substitute sample proportion in (2) to get margin of error

margin of error=0.34 -sample proprtion

=0.34-0.29

=0.05

The margin of error is 0.05

alpha/2=0.10/2=0.05

The sample proportion based on the collected data is 0.29

The margin of error is 0.05

alpha/2=0.05