10.7 Test the claim that average game attendance for home baseball games of the St. Louis Cardinals is 43,853. A sample of 50 home games produced a mean of 44,102. The population standard deviation is 625. Use α = .05.
Solution :
= 43853
=44102
=625
n = 50
This is the two tailed test .
The null and alternative hypothesis is
H0 : =43853
Ha : 43853
Test statistic = z
= ( - ) / / n
= (44102 -43853) /625 / 50
= 2.817
p(Z >2.817 ) = 1-P (Z < 2.817) = 0.0048
P-value = 0.0048
= 0.05
0.0048< 0.05
Reject the null hypothesis .
There is sufficient evidence to suggest that
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