Question

Calculate the p-value for a hypothesis test of a proportion.

The hypotheses are H₀:  H₁: , and the test statistic is z = -2.36. Use the normal distribution to calculate the p-value.

Round your answer to 4 decimal places

Answer 1

Answer:

let us consider,

Ho : p = 0.5

Ha : p != 0.5

For two tailed test,

test statistic z = - 2.36

P value = 0.0182749 [since from z table]

= 0.0183

Here we observe that, p value < alpha(0.05), so we reject Ho. so there is sufficient evidence.

For left tailed,

Ho : p = 0.5

Ha : p < 0.5

P value = P(z < - 2.36)

= 0.0091375 [since from z table]

= 0.0091

Here we observe that, p value < alpha(0.05), so we reject Ho. so there is sufficient evidence.

For right tailed,

Ho : p = 0.5

Ha : p > 0.5

P value = P(z > - 2.36)

= 0.9908625  [since from z table]

= 0.9909

Here we observe that, p value > alpha(0.05), so we fail to reject Ho. so there is no sufficient evidence