Question
n=100 pop. standard deviation= 7.14 confidence interval for the mean was from 47.12-49.92 a) What is...
n=100
pop. standard deviation= 7.14
confidence interval for the mean was from 47.12-49.92
a) What is sample mean
b) What is the margin of error
c) What is the confidence level
Homework Answers
Answer #1
Not the answer you're looking for?
Similar Questions
A sample mean, sample size, population standard deviation, and confidence level are provided. Use this information...
A sample mean, sample size, population standard deviation,
and confidence level are provided. Use this information to complete
parts (a) through (c) below.
x=54, n=14, σ=5, confidence level=99%
A. Use the one-mean z-interval procedure to find a confidence
interval for the mean of the population from which the sample was
drawn.
The confidence interval is from ___to___
B. Obtain the margin of error by taking half the length of the
confidence interval.
What is the length of the confidence interval?...
a. Use the one-mean t-interval procedure with the sample mean, sample size, sample standard deviation, and...
a. Use the one-mean t-interval procedure with the sample mean,
sample size, sample standard deviation, and confidence level
given below to find a confidence interval for the mean of the
population from which the sample was drawn.
b. Obtain the margin of error by taking half the length of the
confidence interval. c. Obtain the margin of error by using the
formula t Subscript alpha divided by 2 Baseline times StartFraction
s Over StartRoot n EndRoot EndFraction .
x=30 n=25...
A sample mean, sample size, population standard deviation, and confidence level are provided. Use this information...
A sample mean, sample size, population standard deviation,
and confidence level are provided. Use this information to complete
parts (a) through (c) below.
x =2323, n=3434, σ=55, confidence level=95%
a.
Use the one-mean z-interval procedure to find a confidence
interval for the mean of the population from which the sample was
drawn.
The confidence interval is from__ to__
b.Obtain the margin of error by taking half the length of the
confidence interval.
What is the length of the confidence interval?...
The margin of error for a confidence interval depends on the confidence level, the standard deviation,...
The margin of error for a confidence interval depends on the
confidence level, the standard deviation, and the sample size. Fix
the confidence level at 95% and the sample standard deviation at 1
to examine the effect of the sample size. Find the margin of error
for sample sizes of 5 to 100 by 5's -- that is, let n = 5, 10, 15,
..., 100. (Round your answers to three decimal places.)
5
10
15
20
25
30
35...
Mean Sample standard deviation Population standard deviation Sample size Confidence level Confidence interval 100 20 na...
Mean
Sample standard deviation
Population standard deviation
Sample size
Confidence level
Confidence interval
100
20
na
25
95 %
100
20
na
25
90 %
100
40
na
25
90 %
100
40
n.a.
16
90 %
100
n.a.
40
16
90 %
How does the confidence level affect the width of the confidence
interval, other things equal?
How does the size of the standard deviation affect the width of
the confidence interval, other things equal?
How does sample size...
The mean and standard deviation of a random sample of n measurements are equal to 33.9...
The mean and standard deviation of a random sample of n
measurements are equal to 33.9 and 3.3, respectively.
a. Find the lower limit, the upper limit and the margin of error
for a 95% confidence interval for m if n = 100.
b. Find the lower limit, the upper limit and the margin of error
for a 95% confidence interval for m if n = 400.
When constructing a confidence interval estimate for a population mean (when the standard deviation of the...
When constructing a confidence interval estimate for a
population mean (when the standard deviation of the population is
known), what is the calculation that has to be made to obtain the
error margin? A. You multiply the number of standard deviations by
the standard deviation of the sampling distribution of sample
means. B. You subtract the sample mean from the population mean and
then divide by the standard deviation of the population. C. You
divide the standard deviation of the...
A simple random sample with n=50provided a sample mean of 23.5 and a sample standard deviation...
A simple random sample with n=50provided a sample mean of 23.5
and a sample standard deviation of 4.3
a. Develop a 90% confidence interval for the
population mean (to 1 decimal).
,
b. Develop a 95% confidence interval for the
population mean (to 1 decimal).
,
c. Develop a 99% confidence interval for the
population mean (to 1 decimal).
,
d. What happens to the margin of error and the
confidence interval as the confidence level is increased?
Assume that population mean is to be estimated from the sample size n =100, Sample mean...
Assume that population mean is to be estimated from the sample
size n =100, Sample mean x = 76.0cm, standard deviation s = 4.0cm.
Use the results to approximate the margin of error and 95%
confidence interval.
c. Confidence Interval given the sample standard deviation: 5. Confidence Interval, σ is not known or...
c. Confidence Interval given the sample standard deviation:
5. Confidence Interval, σ is not known or n<30.
For a group of 20 students taking a final exam, the mean heart
rate was 96 beats per minute and the standard deviation was 5. Find
the 95% confidence interval of the true mean.
e) Find the critical value:
f) Find the margin of error: E =tα/2sn√
g) Find the confidence interval: CI = x−± E.
h) Write the conclusion.
ADVERTISEMENT
Need Online Homework Help?
Get Answers For Free
Most questions answered within 1 hours.
ADVERTISEMENT
Active Questions
asked 4 minutes ago
asked 13 minutes ago
asked 17 minutes ago
asked 44 minutes ago
asked 1 hour ago
asked 1 hour ago
asked 1 hour ago
asked 1 hour ago
asked 1 hour ago
asked 2 hours ago
asked 2 hours ago
asked 2 hours ago