A local newspaper claims in an article that the average income for all handymen in the city is more than $5200 per month. A sample of 20 randomly selected handymen had the mean income of $5300 with the standard deviation of $150 per month. Test the claim made by the local newspaper at α = 0.05 .
For each question you need to find the following
Step 1
b) < 2 points > Write the claim and its opposite , then determine which is the null hypothesis and which is the alternative hypothesis.
c) < 0.5 point >Write the type of test you are going to use ( LT , RT , or 2 T )
d) < 0.5 point > what distribution you are going to use ( z or t )
Step 2
Use a graphing Calculator: Find the calculated test statistic and the P- Value
i) < 0.5 > what did you use to find the CTS : Z- Test, T – Test , or 1-PropZtest ( choose one of them)
ii ) < 2 >Write the value of the calculated test statistics : C. T . S : ( choose z or t ) =
iii) < 1.5 point > P -value =
Step 3 Analyze
Traditional Method < 3 points> P-value Method. < 2 points >
For traditional , you need to Sketch the graph For P-value method, you need to do
Shade the required area P-value α Need to write the value of each
label the critical value/s compare the values ( < or > )
Label the C.T.S
Step 4 : Write
the ______________ that _______________
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