The population of weights of a particular fruit is normally distributed, with a mean of 709 grams and a standard deviation of 39 grams. If 20 fruits are picked at random, then 2% of the time, their mean weight will be greater than how many grams? Round your answer to the nearest gram.
Solution :
Given that ,
mean = = 709
standard deviation = = 39
n = 20
= = 709
= / n = 39 / 20 = 8.7207
The z - distribution of the 2% is,
P( Z > z ) = 2 %
1 - P( Z < z ) = 0.02
P( Z < ) = 1 - 0.02
P( Z < z ) = 0.98
P( Z < 2.054) = 0.98
z = 2.054
Using z - score formula,
X = z * +
= 2.054 * 8.7207 + 709
= 726.9123
= 727 grams
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