Question

use technology to find the P- value for the hypothesis
test described below

the claim is that for a smartphone carrier's data speed at
airports, the mean is mu =19.00 mbps. the sample size n = 14 and
the test statistic is t= 1.118.

how is this entered into a TI 84

Answer #1

We have to compute the p-value here for df = n - 1 = 13 degrees of freedom and t statistic value of t = 1.118.

As we are testing here whether the mean is 19 mbps, this is a two tailed test and the p-value is computed using the calculator as:

1) Calculate t_calc (t_test)

2) Find the absolute value of t_calc

3) 2nd DISTR

4) Scroll down to tcdf

5) ENTER

6) Now enter: 1.118 , 1000, 13 )

7) ENTER

8) Output is ½ of the P-value so

9) Multiply result by 2

The output here is: 0.2838

**Therefore 0.2838 is the required p-value
here.**

se technology to find the P-value for the hypothesis test
described below.
The claim is that for a smartphone carrier's data speeds at
airports, the mean is
muμequals=16.00
Mbps. The sample size is
nequals=14
and the test statistic is
tequals=negative −2.404.
P-valueequals=nothing
(Round to three decimal places as needed.)
se technology to find the P-value for the hypothesis test
described below.
The claim is that for a smartphone carrier's data speeds at
airports, the mean is
muμequals=16.0016.00
Mbps. The sample...

Use technology to find the P-value for the hypothesis test
described below. The claim is that for a smartphone carrier's data
speeds at airports, the mean is muequals11.00 Mbps. The sample
size is nequals22 and the test statistic is tequals1.797.

Use
technology to find the P-value for the hypothesis test described
below.
The claim is that for a smartphone carrier’s data speeds at
airports, the mean is u= 14 mbps. The sample size is n=18 and the
test statistic is t= -2.055.

se technology to find the P-value for the hypothesis test
described below.
The claim is that for a smartphone carrier's data speeds at
airports, the mean is
muμequals=12.00
Mbps. The sample size is
nequals=17
and the test statistic is
tequals=1.118
P-valueequals= 0.025
(Round to three decimal places as needed.)

Use technology to find the P-value for the hypothesis test
described below. The claim is that for a smartphone carrier's data
speeds at airports, the mean is muμequals=17.00Mbps. The sample
size is nequals=26 and the test statistic is tequals=2.336

Use technology to find the? P-value for the hypothesis test
described below.
The claim is that for 12 AM body? temperatures, the mean is
mu?greater than>98.698.6degrees°F.
The sample size is
nequals=88
and the test statistic is
tequals=1.4641.464.

The claim is that for a smartphone carrier's data speeds at
airports, the mean is μ=18.00 Mbps. The sample size is n=1717 and
the test statistic is t=−1.976.

The display provided from technology available below results
from using data for a smartphone carrier's data speeds at airports
to test the claim that they are from a population having a mean
less than
4.00
Mbps. Conduct the hypothesis test using these results. Use a
0.05
significance level. Identify the null and alternative
hypotheses, test statistic, P-value, and state the final
conclusion that addresses the original claim.
LOADING...
Click the icon to view the display from technology.
Assuming all conditions...

The display provided from technology available below results
from using data for a smartphone carrier's data speeds at airports
to test the claim that they are from a population having a mean
less than 6.00 Mbps. Conduct the hypothesis test using these
results. Use a 0.050 significance level. Identify the null and
alternative hypotheses, test statistic, P-value, and state the
final conclusion that addresses the original claim.
null? hypotheses?
z= ??
p-vale?
conclusion? evidence or not enough evidence?

A. Find the p-value of a 2 sided 95% confidence test of
hypothesis if the value found for the sample mean was 14.53 the
Null Hypothesis assumes that the population mean is Mu = 14, the
population standard deviation is 3 and the sample size is 14
B. Find the p-value of a 2-sided 95% confidence test of
hypothesis if the value found for the sample mean was 35.71 the
Null Hypothesis assumes that the population mean is Mu =...

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 3 minutes ago

asked 12 minutes ago

asked 12 minutes ago

asked 24 minutes ago

asked 35 minutes ago

asked 38 minutes ago

asked 46 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago