Question

A genetic experiment involving peas yielded one sample of offspring consisting of

410410

green peas and

179179

yellow peas. Use a

0.050.05

significance level to test the claim that under the same​ circumstances,

2727​%

of offspring peas will be yellow. Identify the null​ hypothesis, alternative​ hypothesis, test​ statistic, P-value, conclusion about the null​ hypothesis, and final conclusion that addresses the original claim. Use the​ P-value method and the normal distribution as an approximation to the binomial distribution.

What are the null and alternative​ hypotheses?

A.

Upper H 0 : p not equals 0.27H0: p≠0.27

Upper H 1 : p less than 0.27H1: p<0.27

B.

Upper H 0 : p not equals 0.27H0: p≠0.27

Upper H 1 : p greater than 0.27H1: p>0.27

C.

Upper H 0 : p equals 0.27H0: p=0.27

Upper H 1 : p not equals 0.27H1: p≠0.27

Your answer is correct.

D.

Upper H 0 : p equals 0.27H0: p=0.27

Upper H 1 : p less than 0.27H1: p<0.27

E.

Upper H 0 : p equals 0.27H0: p=0.27

Upper H 1 : p greater than 0.27H1: p>0.27

F.

Upper H 0 : p not equals 0.27H0: p≠0.27

Upper H 1 : p equals 0.27H1: p=0.27

What is the test​ statistic?

zequals=1.851.85

​(Round to two decimal places as​ needed.)

What is the​ P-value?

​​(Round to four decimal places as​ needed.)

Answer 1