Question

We have a 2x2 table, with two variables. We run a chisquare test on it. The results are as follow:

chi.sq= 4.0231

degrees of freedom = 1

p-value = 0.04488

Answer questions below (true/false) and explain why you chose that answer:

1. The degrees of freedom was 1, because there were two variables.

2. The result would be significant with alpha = .5.

3. The degrees of freedom was 1 because there were four cells

4. The degrees of freedom was 1 because it was a 2x2 table.

Answer 1

Sol:

degrees of freedom=(r-1)(c-1)

its a 2*2 table

so 2 rows and 2 columns

df=(2-1)(2-1)

=1

p=0.04488

p<0.05

Reject Ho

Accept Ha

1. The degrees of freedom was 1, because there were two variables.

FALSE as df=(r-1)(c-1)

r=no of rows

c=no of columns

2. The result would be significant with alpha = .5.

TRUE

alpha=0.05

p=0.04488

p<0.05

Reject Ho

And accept Ha

Conclude that result would be significant

3. The degrees of freedom was 1 because there were four cells

FALSE

as df is calculated as df=(r-1)(c-1)

4. The degrees of freedom was 1 because it was a 2x2 table.

TRUE

as df=(r-1)(c-1)=(2-1)(2-1)=1