Question

The t-test paired scores go like that: t = 8.812, df = 46, p-value = 0.00000000001936...

The t-test paired scores go like that:

t = 8.812, df = 46, p-value = 0.00000000001936
CI (95%): 3.677283 & 5.854632
The mean of the differences: 4.765957
Decide whether statements below are true and explain why:
1) Classical hypothesis testing would recognize a significant difference here
2) Because the estimates of means are different, with 95% there is a difference between the means in the (imaginary) population,

3)The confidence interval includes 0, so it’s possible that there is no real difference,

4) The top confidence interval is quite high, so it would tell us, that likely there is a real difference between the means

Homework Answers

Answer #1

The solution to this problem is given by

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
T test results- t-statistic, df, p-value. What the output means, both statistically and in terms of...
T test results- t-statistic, df, p-value. What the output means, both statistically and in terms of differences between the sites? t(5) = -5.11, p=0.0037 Anova results- F-statistic, df (between and within groups), p-value. What the output means, both statistically and in terms of differences between the sites? F(5, 36) = 4.26, p=0.0038 Linear Regression results-F-statistic, df (regression and residual), p-value, R2. What the output means, both statistically and in terms of differences between the sites? F(1,91)=794, p=0.011, R2=0.90
Using SPSS, the outcome of the data analysis are as follow; Paired Differences 95% Confidence Interval...
Using SPSS, the outcome of the data analysis are as follow; Paired Differences 95% Confidence Interval of the difference Mean Std. Deviation Std. Error Mean Lower Upper T df Sig.(2-tailed) Pair 1 Method A-Method B 5.200 6.125 1.937 0.819 9.581 2.685 9 1-Provide a statement about the finding in this table for paired t-test and it is interpretation? 2-Report the estimate difference for ua-ub between the mean scores obtained by children taught by the two methods and its 95% confidence...
A researcher doing a paired T Test obtains a p-value of 0.026 when testing the hypotheses...
A researcher doing a paired T Test obtains a p-value of 0.026 when testing the hypotheses H0:ud = 0 and Ha: ud =/ 0. If she also computes a 99% confidence interval for the mean difference, which of the following should she expect? Answers: Zero will be in the confidence interval because 0.026 < 0.05 Zero will not be in the confidence interval because 0.026 > 0.01 Zero will not be in the confidence interval because 0.026 < 0.05 Zero...
Paired T confidence interval: μD = μ1 - μ2 : Mean of the difference between Male...
Paired T confidence interval: μD = μ1 - μ2 : Mean of the difference between Male Population and Female Population 90% confidence interval results: Difference Mean Std. Err. DF L. Limit U. Limit Male Population - Female Population -4443.9378 721.71083 594 -5632.9008 -3254.9748 Why is the above data paired? Interpret and state your confidence Interval, and based on your confidence interval is there a significant difference in male and female populations; if so what is it and how do you...
Now suppose a larger sample (30 pairs vs 10 pairs) was collected and a paired t...
Now suppose a larger sample (30 pairs vs 10 pairs) was collected and a paired t test was used to analyze the data. The output is shown below. Paired Samples Statistics Mean N Std. Deviation Std. Error Mean Pair 1 Female salaries 6773.33 30 782.099 142.791 Male salaries 7213.33 30 875.227 159.794 Paired Samples Correlations N Correlation Sig. Pair 1 Female salaries & Male salaries 30 .881 .000 Paired Samples Test Paired Differences t df Sig. (2-tailed) Mean Std. Deviation...
Independent Samples T-Test 95% CI for Mean Difference t df p Mean Difference SE Difference Lower...
Independent Samples T-Test 95% CI for Mean Difference t df p Mean Difference SE Difference Lower Upper Cohen's d Reading Level 1.995 69 0.003 0.878 0.289 0.293 1.493 0.721 The test is: Conduct a two-independent samples t test to determine if people with high IQs differ reading level compared to people without a high IQ. Using this table, first state if this test is directional or non directional. write the test results for a two-independent samples t-test. State which value...
Assume that the population of paired differences is normally distributed. 3) A test of writing ability...
Assume that the population of paired differences is normally distributed. 3) A test of writing ability is given to a random sample of students before and after they completed a formal writing course. The results are given below. Construct a 99% confidence interval for the mean difference between the before and after scores. Before 70 80 92 99 93 97 76 63 68 71 74 After 69 79 90 96 91 95 75 64 62 64 76 (a) Find the...
> x=c(5,3,1,6,4,3,2,6,7) > y=c(7,4,1,8,5,2,4,7,9) > mean(x) [1] 4.111111 > mean(y) [1] 5.222222 > cor(x,y) # +...
> x=c(5,3,1,6,4,3,2,6,7) > y=c(7,4,1,8,5,2,4,7,9) > mean(x) [1] 4.111111 > mean(y) [1] 5.222222 > cor(x,y) # + indicates consistency, more power [1] 0.943973 > t.test (x,y,paired=T) #sig because of + correlation    Paired t-test data: x and y t = -3.1623, df = 8, p-value = 0.01335 alternative hypothesis: true difference in means is not equal to 0 95 percent confidence interval: -1.9213584 -0.3008638 sample estimates: mean of the differences              -1.111111 > What conclusions can be made regarding statistical significance? Would...
Given two dependent random samples with the following results: Population 1 45 46 27 36 38...
Given two dependent random samples with the following results: Population 1 45 46 27 36 38 33 15 Population 2 42 32 42 41 25 28 19 Use this data to find the 95% confidence interval for the true difference between the population means. Let d = (Population 1 entry -- (Population 2 entry). Assume that both populations are normally distributed. Solution: Step 1. Find the mean of the paired differences, d-bar . Round your answer to one decimal place....
Scenario 3: t-test Analysis Paired Samples Statistics Mean N Std. Deviation Std. Error Mean Pair 1...
Scenario 3: t-test Analysis Paired Samples Statistics Mean N Std. Deviation Std. Error Mean Pair 1 T1 Scale of student's mathematics utility -.0096 16021 .99040 .00782 T2 Scale of student's mathematics utility .0059 16021 1.00682 .00795 Paired Samples Correlations N Correlation Sig. Pair 1 T1 Scale of student's mathematics utility & T2 Scale of student's mathematics utility 16021 .285 .000 Paired Samples Test Paired Differences t df Sig. (2-tailed) Mean Std. Deviation Std. Error Mean 95% Confidence Interval of the...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT