A researcher wishes to estimate the number of hours family households spend on heating their homes. The standard deviation was said to be 5.9 with a standard error of 0.8. What size sample should be obtained if she wants to be 95% Confident?
Solution
standard deviation =s = = 5.9
Margin of error = E = 0.8
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2 = Z0.025 = 1.96
sample size = n = [Z/2* / E] 2
n = ( 1.96*5.9/ 0.8)2
n =208.95
n=209 rounded
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