Question

A survey of 2045 randomly chosen home loan customers from a large bank found that 175...

A survey of 2045 randomly chosen home loan customers from a large bank found that 175 had been late with their payments at least once in the previous 12 months. Which of the following is a 95% confidence interval for the proportion of all customers that have been late with their payments at least once in the previous 12 months?

Select one:

a. (0.0735, 0.0977)

b. (-0.1942, 0.3653)

c. (0.0794, 0.0918)

d. (0.08550, 0.08564)

e. (0.0678, 0.02389)

2.

In a hypothesis testing for comparing population means µ1 and  µ2 , independent samples from each of the two populations were collected and measurements were taken. The population standard deviations are not known. Given the null hypothesis Ho: µ1= µ2 the alternative hypothesis Ha: µ1 ≠ µ2, and P-value =0.037. Which of the following statements is correct ?

The appropriate hypothesis test is :

Select one:

a. one-sample z-test

b. paired-sample t-test

c. two-independent-sample t-test

d. paired-sample z-test

e. two-independent-sample z-test

f. one-sample t-test

3.

In a hypothesis testing for comparing population means µ1 and  µ2 , independent samples from each of the two populations were collected and measurements were taken. The population standard deviations are not known. Given the null hypothesis Ho: µ1= µ2 the alternative hypothesis Ha: µ1 ≠ µ2, and P-value =0.037. Which of the following statements is correct ?

Select one:

a. Do not reject the null hypothesis at the significance level of 0.05 (α=0.05)

b. The decision to reject or not to reject the null hypothesis cannot be made because the sample sizes were not given.

c. Reject the null hypothesis at the significance level of 0.01 (α=0.01)

d. Reject the null hypothesis at the significance level of 0.5 (α=0.5)

please provide as soon as possible.

Homework Answers

Answer #1

Solution-1:

z crit for 95%=1.96

sample prportion late with their payments at least once in the previous 12 months

=p^=x/n=175/2045= 0.08557457

95% confidence interval for p is

0.08557457-1.96*sqrt( 0.08557457*(1- 0.08557457)/2045), 0.08557457+1.96*sqrt( 0.08557457*(1- 0.08557457)/2045)

0.07345029, 0.09769885

a. (0.0735, 0.0977)

Solution-2:

. The population standard deviations are not known. so its a t test

and samples are indpendent ,independent samples t test

c. two-independent-sample t-test

Solution-3:

p=0.037

alpha=0.05

p<0.05

Reject Ho

Accept Ha

d. Reject the null hypothesis at the significance level of 0.5 (α=0.5)

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