From past record, it is known that a travelling time
for a bus from Alor Setar to Kuala Lumpur
are normal distributed with mean 6 hours and standard deviation 1.5
hours. Find probability when
the mean for a random selected of 5 buses are:
i. At most 5 hours
ii. Between 5 and 7 hours
iii. At least 5.5 hours
Given
Let be the sample mean of 5 buses
The sampling distribution of sample mean follow Normal with
mean = 6
and standard error = 1.5/\sqrt{5}=0.6708
that is
then
i)
= P( z < -1.49)
= 0.0681 ( from z table)
Answer : Probability = 0.0681
ii)
= P(-1.49 < z < 1.49)
= 0.8638 (from z table)
Answer : Probability = 0.8636
iii)
= P( z >- 0.75 )
= 0.7297 ( from z table)
Answer : Probability = 0.7297
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