Listed below are student evaluation ratings of courses, where a rating of 5 is for "excellent." The ratings were obtained at one university in a state. Construct a confidence interval using a
95%
confidence level. What does the confidence interval tell about the population of all college students in the state?
4.1,2.8, 3.8,4.8,3.2,4.1,3.7,4.4,4.5,4.4,4.1,3.7,
3.2,4.1, 3.6
Here sample mean is
Create the following table.
data | data-mean | (data - mean)2 |
4.1 | 0.2 | 0.04 |
2.8 | -1.1 | 1.21 |
3.8 | -0.1 | 0.01 |
4.8 | 0.9 | 0.81 |
3.2 | -0.7 | 0.49 |
4.1 | 0.2 | 0.04 |
3.7 | -0.2 | 0.04 |
4.4 | 0.5 | 0.25 |
4.5 | 0.6 | 0.36 |
4.4 | 0.5 | 0.25 |
4.1 | 0.2 | 0.04 |
3.7 | -0.2 | 0.04 |
3.2 | -0.7 | 0.49 |
4.1 | 0.2 | 0.04 |
3.6 | -0.3 | 0.09 |
Find the sum of numbers in the last column to get.
So standard deviation is
Lets assume that distribution is normal
So t value for 95% CI is TINV(0.05,14)=2.145
Hence Margin of Error is
So CI is
Hence proportion of student evaluation ratings of courses in the population will lie in the range of 3.597 to 4.203
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