Find a 90% confidence interval for a population mean ? for these values. (Round your answers to three decimal places.)
(a)
n = 145, x = 0.88, s2 = 0.084
to
(b)
n = 70, x = 25.6, s2 = 3.49
to
(c)
Interpret the intervals found in part (a) and part (b).
There is a 10% chance that an individual sample proportion will fall within the interval.There is a 90% chance that an individual sample proportion will fall within the interval. 90% of all values will fall within the interval.In repeated sampling, 90% of all intervals constructed in this manner will enclose the population mean.In repeated sampling, 10% of all intervals constructed in this manner will enclose the population proportion.
Here we apply t test for finding Confidence Interval because population standard deviation is unknown.
a) 90% Confidence Interval
Degrees of freedom (df) = n-1 = 145-1 = 144
= (0.840, 0.920)
b) 90% Confidence Interval
Degrees of Freedom (df) = n-1 = 70-1 = 69
=( 25.228, 25.972)
c) Interpretation : .In repeated sampling, 90% of all intervals constructed in this manner will enclose the population mean
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