The times per week a student uses a lab computer are normally distributed, with a mean of 6.1 hours and a standard deviation of 1.3 hours. A student is randomly selected. Find the following probabilities.
(a) Find the probability that the student uses a lab computer less than 4 hours per week.
(b) Find the probability that the student uses a lab computer between 7 and 8 hours per week.
(c) Find the probability that the student uses a lab computer more than 9 hours per week.
Given,
= 6.1
= 1.3
a) find p(x< 4)
We know that z=(x-) /
p(x < 4) = 0.5 - p(z < 4-6.1/1.3)
= 0.5 - p(z < -1.62)
= 0.5 - 0.4474
p(x < 4) = 0.0526
Therefore probability that student uses computer lab less than 4 is 0.0526.
2) p(7 < x < 8) = p(z < 8-6.1/1.3) - p(z < 7-6.1/1.3)
= p(z < 1.46) - p(z < 0.69)
= 0.4279 - 0.2549
p(7 < x < 8) = 0.173
Therefore probability that student uses computer lab in between 7 and 8 is 0.2156.
3) p(x > 9)
p(x > 9) = 0.5 - p(z < 9-6.1/1.3)
= 0.5 - p(z < 2.23)
= 0.5 - 0.4871
p(x > 9) = 0.0129
Therefore the probability that the student uses computer lab is more than 9 hours is 0.0129.
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