We want to compare the serum cholesterol levels of recent immigrants with the levels found in the general population of the US. It is known that the mean cholesterol level for a certain age group in the US is 190 mg/dL. A random sample of 100 recent immigrants of the same age group finds a mean of 181.52 mg/dL. Assume that a population standard deviation is 48.23. Test at the 5% level to see if the level for recent immigrants is different. Give the null and alternate hypotheses. Decide if you accept or reject the null hypothesis.
Solution :
This is the two tailed test,
The null and alternative hypothesis is ,
H0 : = 190
Ha : 190
Test statistic = z
= ( - ) / / n
= (181.2 - 190) / 48.23 / 100
Test statistic = z = -1.82
P (Z < -1.82) = 0.0344
P-value = 2 * P (Z < -1.82)
P-value = 2 * 0.0344
P-value = 0.0688
= 0.05
P-value >
Fail to reject the null hypothesis .
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