Parents have always wondered about the sex of a child before it is born. Suppose that the probability of having a male child was 0.5, and that the sex of one child is independent of the sex of other children. What is the probability of having more than 2 girls out of 10 children? Round your answer to four decimal places.
We have the probability of having a male child was 0.5
So probability of having female child is 1-0.5=0.5
therefore p=0.5
Consider for 10 children
Hence n=10
The sex of one child is independent of the sex of other children.
Therefore this is binomial distribution.
X~B(n=10, p=0.5)
The probability of having more than 2 girls out of 10 children is,
Hence The probability of having more than 2 girls out of 10 children is 0.9453
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