An engineer is going to redesign an ejection seat for an airplane. The seat was designed for pilots weighing between 130 lb and 181 lb. The new population of pilots has normally distributed weights with a mean of 135 lb and a standard deviation of 25.4 lb.
If a pilot is randomly selected, find the probability that his weight is between 130 lb and 181 lb.
This is a normal distribution question with
This implies that
P(130.0 < x < 181.0) = P(-0.1969 < z < 1.811) = P(Z < 1.811) - P(Z < -0.1969)
P(130.0 < x < 181.0) = 0.9649295741655715 - 0.4219528968394331
P(130.0 < x < 181.0) = 0.543
PS: you have to refer z score table to find the final probabilities.
Please hit thumbs up if the answer helped you
Get Answers For Free
Most questions answered within 1 hours.