Given that z is a standard normal random variable, compute the following probabilities (to 4 decimals). P(-1.98 ≤ z ≤ 0.48) P(0.55 ≤ z ≤ 1.29) P(-1.73 ≤ z ≤ -1.08)
P(-1.98 z 0.48) = P(z < 0.48) - P(z < -1.98)
= 0.6844 - 0.0239
= 0.6605
P(0.55 z 1.29) = P(z < 1.29) - P(z < 0.55)
= 0.9015 - 0.7088
= 0.1927
P(-1.73 z -1.08) = P(z < -1.08) - P(z < -1.73)
= 0.1401 - 0.0418
= 0.0983
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