Suppose that the walking step lengths of adult males are normally distributed with a mean of 2.3 feet and a standard deviation of 0.20 feet. A sample of 82 men’s step lengths is taken.
Step 2 of 2 :
Find the probability that the mean of the sample taken is less than 2.1 feet. Round your answer to 4 decimal places, if necessary.
Solution :
_{} = / n = 0.20 / 82
P( < 2.1) = P(( - _{} ) / _{} < (2.1 - 2.3) / 0.20 / 82)
= P(z < -9.06)
= 0
Probability = 0
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